20x^2=44

Solution for 20x^2=44 equation:

20x^2=44

We move all terms to the left:

20x^2-(44)=0

a = 20; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·20·(-44)
Δ = 3520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3520}=\sqrt{64*55}=\sqrt{64}*\sqrt{55}=8\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{55}}{2*20}=\frac{0-8\sqrt{55}}{40}
=-\frac{8\sqrt{55}}{40}
=-\frac{\sqrt{55}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{55}}{2*20}=\frac{0+8\sqrt{55}}{40}
=\frac{8\sqrt{55}}{40}
=\frac{\sqrt{55}}{5}
$